A string of pearls such that 1/3 is lost and of that 1/4th is missing, remaining is 20 then actual number of pearls?
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Let the actual number of pearls in the string be x
Out of the total pearls, 1/3rd is lost, 1/4th is missing and remaining is 20.
According to the question.
x/3 + x/4 + 20/1 = x/1
Taking the L.C.M. of the denominators and then solving it.
⇒ (4x + 3x + 240)/12 = x/1
Now, Cross multiplication
7x + 240 = 12x
12x - 7x = 240
5x = 240
x = 240/5
x = 48
The actual number of pearls were 48
____________________________________________________________
Let us check our answer.
1/3rd is lost
= 48/3
= 16 pearls were lost
1/4th is missing
= 48/4
= 12 pearls were missing
20 pearl are remaining
Actual number of pearls = 16 + 12 + 20 = 48
Our answer is correct.
Out of the total pearls, 1/3rd is lost, 1/4th is missing and remaining is 20.
According to the question.
x/3 + x/4 + 20/1 = x/1
Taking the L.C.M. of the denominators and then solving it.
⇒ (4x + 3x + 240)/12 = x/1
Now, Cross multiplication
7x + 240 = 12x
12x - 7x = 240
5x = 240
x = 240/5
x = 48
The actual number of pearls were 48
____________________________________________________________
Let us check our answer.
1/3rd is lost
= 48/3
= 16 pearls were lost
1/4th is missing
= 48/4
= 12 pearls were missing
20 pearl are remaining
Actual number of pearls = 16 + 12 + 20 = 48
Our answer is correct.
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