a student secured 36% marks in an examination and failed by 32 marks. Another student secured 43% marks and got 24 marks more than the minimum pass marks . find the maximum marks.
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Answered by
37
Let the maximum marks be x.
Marks scored by first = 36% of x= 36x/100
Passing marks = 36x/100 + 32
Marks scored by second = 43% of x = 43x/100
Passing marks= 43x/100-24
36x/100+32 = 43x/100 -24
7x/100= 56
x= 800
Maximum marks= 800
Marks scored by first = 36% of x= 36x/100
Passing marks = 36x/100 + 32
Marks scored by second = 43% of x = 43x/100
Passing marks= 43x/100-24
36x/100+32 = 43x/100 -24
7x/100= 56
x= 800
Maximum marks= 800
Answered by
5
Step-by-step explanation:
Maximim mark =800
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