Question

a student uses a lens of focal length + 50 cm and another student is a lens of - 50 cm discuss the nature and find power of lens​

Answer 1

real and virtual and power of lens is negative

Answer 2

1 case:

f=+50

as the sign is +,so the nature of the lens is Real and inverted

P=1/f(in m)

P=1/-0.5

P=-2 D

2 case:

f=-50

therefore nature of lens is virtual and erect

P=1/0.5

=+2 D

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