Question

A student was absent for 12 days out of 195 days in an academic year. Find his attendance % in that academic year

Answer 1

Total no. of days= 195

Total he absent= 12

so, Total he present = 195-12

= 183

his attendance percentage =

$his attendance percentage = \: \: \frac{183}{195} \times 100\\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \: 93.84 \: percent$

Hope it helps you

Answer 2

Answer:

total number of days=195

total number of days he was absent=12

number of days he was present=195-12=183

percentage=(number of days he was present÷total number of days)×100

=183÷195×100=23.46%