Math, asked by TbiaSamishta, 1 year ago

A study was conducted to find out the concentration of sulphur dioxide in the air in parts per million (ppm) of a certain city. The data obtained for 30 days is as follows.0.03 0.08 0.08 0.09 0.04 0.17
0.16 0.05 0.02 0.06 0.18 0.20
0.11 0.08 0.12 0.13 0.22 0.07
0.08 0.01 0.10 0.06 0.09 0.18
0.11 0.07 0.05 0.07 0.01 0.04
For how many days, was the concentration of sulphur dioxide more than 0.11 parts per million?

Answers

Answered by hukam0685
25
Hello,

Solution:Data obtained for 30 days

0.03 0.08 0.08 0.09 0.04 0.17

0.16 0.05 0.02 0.06 0.18 0.20
0.11 0.08 0.12 0.13 0.22 0.07
0.08 0.01 0.10 0.06 0.09 0.18
0.11 0.07 0.05 0.07 0.01 0.04

Grouped the data for easy calculation (0.01-0.05) 0.05 not included

Group _________frequency

0.01-0.05__________6

0.05-0.10__________13

0.10-0.15___________5

0.15-0.20__________4

0.20-0.25__________2


Now,we can easily check for how many days

concentration of sulphur dioxide more than 0.11

parts per million?

Answer: 8 days

from class 0.10-0.15 we exclude 3 values namely 0.10,0.11 and 0.11

Hope it helps you
Answered by yogitamishra30
19

here is your answer it might help you please mark as brainliest

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