Question

A submarine travels 2.4 km due East from its base and then turns and travels due North for 14.8 km. How far away is the submarine from its base?

Answer 1

Answer:

let the distance be x

by Pythagoras

Step-by-step explanation:

${2.4}^{2} + {14.8}^{2} = {x}^{2} \\ 5.76 + 219.04 = {x}^{2} \\ x = \sqrt{224.8}$

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