how to find diagnol of square or rectangle.
Answers
Answered by
2
Answer:
Step-by-step explanation:
Diagonal of a Square
Diagonal of square=a2–√
Where, a is the length of the side of the square
Diagonal of a Rectangle
DiagonalofaRectangle=l2+b2−−−−−√
Where,
l is the length of the rectangle.
b is the breadth of the rectangle.
p and q are the diagonals
Answered by
1
Okay so it’s pretty simple
To derive the diagonal of a rectangle we need to have an understanding of the gougu theorem or Pythagoras theorem
Since we know that the opposite sides of a rectangle are equal let the sides be ‘a’ and ‘b’. So on applying Pythagoras theorem for the diagonal we have
(Diagonal)^2=a^2+b^2
Hence the diagonal becomes
(Diagonal)= sqrt(a^2+b^2)
Hence diagonal of a rectangle is equal to the square root of the addition of squares of the two adjacent sides
Now for square just put a=b as square is a special kind of rectangle which has all sides to be equal.
We have
For square =
Diagonal=sqrt(a^2+a^2)
Which is equal to
=> a times the sqrt(2)
=> a*sqrt(2)
Hope it helps :)
To derive the diagonal of a rectangle we need to have an understanding of the gougu theorem or Pythagoras theorem
Since we know that the opposite sides of a rectangle are equal let the sides be ‘a’ and ‘b’. So on applying Pythagoras theorem for the diagonal we have
(Diagonal)^2=a^2+b^2
Hence the diagonal becomes
(Diagonal)= sqrt(a^2+b^2)
Hence diagonal of a rectangle is equal to the square root of the addition of squares of the two adjacent sides
Now for square just put a=b as square is a special kind of rectangle which has all sides to be equal.
We have
For square =
Diagonal=sqrt(a^2+a^2)
Which is equal to
=> a times the sqrt(2)
=> a*sqrt(2)
Hope it helps :)
Similar questions