Question

a suitcase with measure 80 CM x 48 cm x 24cn is to be covered with a tarpaulin cloth. How many meters of tarpaulin of width 96cm is required to cover 100 such suitcase?

Answer 1

$\huge \: hello$

$\huge \: here \: is \: your \: answer$

$-> Surface area of suitcase (cuboid) = 2(l \times b + b \times h + l \times h)$

= 2(80 x 48 + 48 x 24 + 24 x 80)

= 2(3840 + 1152 + 1920)

$= {13824cm}^{2}$


$Surface area of 100 suitcase = 13824 \times 100$

$= {1382400cm}^{2}$


Required trapaulin = Length x Breath

$= {1382400cm}^{2} = length \times 96cm$

$length = (\frac{1382400}{96} ) = 14400cm = 144m$


144 metres of tarpaulin of width 96cm is required to cover 100 such suitcase.

$\huge \frac{thanks}{hope \: you \: like \: my \: answer}$

Answer 2

Given:

• Suitcase Measure = 80cm × 48 cm × 24 cm

• Tarpaulin width = 96 cm

• Total Suitcases = 100

Solution

• Length of suitcase box (l) = 80 cm
• Breadth of suitcase box (b) = 48 cm
• Height of cuboidal box (h) = 24 cm

Total surface area of suitcase box = 2(lb + bh + hl)

$\implies$ 2(80 × 48 + 48 × 24 + 24 × 80)

$\implies$ 2 (3840 + 1152 + 1920)

$\implies$ 2 (6912)

$\implies$ 2 × 6912

$\implies$ 13824 cm²

• Total surface area of suitcase box is 13824 cm²

Area of Tarpaulin cloth = Surface area of suitcase

$\implies$ l × b = 13824

$\implies$ l ×96 = 13824

$\implies$ l = 13824/96

$\implies$ l = 144 cm

Required tarpaulin for 100 suitcases l;

$\implies$ 144 × 100

$\implies$ 14400 cm

$\implies$ 144 m

Hence,

• Tarpaulin cloth required to cover 100 suitcases is 144 m .