A sulphuric acid solution containing 571.4 gram of H2SO4 per litre of the solution has a density of 1.329 gram per centimetre cube. Calculate the molality, molarity and mole fraction of H2SO4 in this solution.
Answers
Explanation:
H2SO4
H2SO4mass of the solution = d x V = 1.329 x 1000 = 1329 g
H2SO4mass of the solution = d x V = 1.329 x 1000 = 1329 g%C = mass solute / d V x(100)
H2SO4mass of the solution = d x V = 1.329 x 1000 = 1329 g%C = mass solute / d V x(100)The mass % for the density of the solution does not correspond
H2SO4mass of the solution = d x V = 1.329 x 1000 = 1329 g%C = mass solute / d V x(100)The mass % for the density of the solution does not correspondto 1.329 g/mL (density) it corresponds to 35.9%
H2SO4mass of the solution = d x V = 1.329 x 1000 = 1329 g%C = mass solute / d V x(100)The mass % for the density of the solution does not correspondto 1.329 g/mL (density) it corresponds to 35.9%m =%CDV
H2SO4mass of the solution = d x V = 1.329 x 1000 = 1329 g%C = mass solute / d V x(100)The mass % for the density of the solution does not correspondto 1.329 g/mL (density) it corresponds to 35.9%m =%CDVm = 0.359 x 1.329 x 1000 mL = 477.11 (mass solute)
H2SO4mass of the solution = d x V = 1.329 x 1000 = 1329 g%C = mass solute / d V x(100)The mass % for the density of the solution does not correspondto 1.329 g/mL (density) it corresponds to 35.9%m =%CDVm = 0.359 x 1.329 x 1000 mL = 477.11 (mass solute)477.11/98 g/mol = 4.87 mol
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4.87 mol/1 L = 4.87 M
Answer:
A sulfuric acid solution containing 571.4gof H2SO4per liter of solution has a density of 1.329 g/cm3.
PartA
Calculate the mass percentage of H2SO4in this solution.
Express your answer using four significant figures.
PartB
Calculate the mole fraction of H2SO4in this solution.
Express your answer using four significant figures.
PartC
Calculate the molality of H2SO4in this solution.
Express your answer using four significant figures.
PartD
Calculate the molarity of H2SO4in this solution.
Express your answer using four significant figures.