Question

A sum of money put at 11% per annum amount to 4491 in 2 year 3 month. What will it amount to in 3 years at the same rate.

Answer 1

SI=A-P
=4491-P

now ,
4491-P=P x r x t/100
=P x 11 x 9/2 /100
=99P/200
4491=299P/200

P=4491 x 200/299
now ,
SI=P x 11 x 3/100
=4491 x 200/299 x 11 x 3/100
=4491 x 2 x 33/299
=991.3 Rs

Answer 2

Answer:

$\sf\large\underline{Given:-}$

$\sf{\implies Amount=Rs.4491}$

$\sf{\implies Rate=11\%}$

$\sf{\implies Time= 2\:years\:3\:months}$

$\sf\large\underline{To\: Find:-}$

$\sf{\implies Amount\:_{(after\:3\: years)}=?}$

$\sf{\implies Principal=?}$

$\sf\large\underline{Solution:-}$

To calculate the amount after 3 years at first we have to assume the sum of money be P then calculate amount after 3 years. By applying formula we can easily find the amount.

$\sf\large\underline{Formula\:used:-}$

$\tt{\implies SI=Amount-Principal}$

$\tt{\implies SI=4491-P}$

Now calculate principal here:]

Here T=24+3/12=27/12=9/4

$\tt{\implies P=\dfrac{SI*100}{T*R}}$

$\tt{\implies P=\dfrac{(4491-P)*100*4}{9*11}}$

$\tt{\implies P=\dfrac{(4491-P)*100*4}{99}}$

$\tt{\implies P=\dfrac{(4491-P)*400}{99}}$

$\tt{\implies P=\dfrac{898200-400P}{99}}$

$\tt{\implies 99P=1796400-400P}$

$\tt{\implies 99P+400P=1796400}$

$\tt{\implies 499P=1796400}$

$\tt{\implies P=Rs.3600}$

Now calculate SI for 3 years:]

$\tt{\implies SI=\dfrac{P*R*T}{100}}$

$\tt{\implies SI=\dfrac{3600*11*3}{100}}$

$\tt{\implies SI=\dfrac{3600*33}{100}}$

$\tt{\implies SI=36*33}$

$\tt{\implies SI=1188}$

Now calculate amount for 3 years:]

$\tt{\implies Amount=P+SI}$

$\tt{\implies Amount=3600+1188}$

$\tt{\implies Amount=Rs.4788}$

$\sf\large{Hence,}$

$\sf{\implies Amount\:_{(after\:3\: years)}=Rs.4788}$