A sum of money was distributed equally among a certain number of children . If there were 10 children more, each would get a rupee less. But if there were 15 children less,each would get 3 rupees more. Find the sum of money and also the number of children.
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Let the sum of rupee be x no of boys be y then each boy get x/y now if the no of boys increased by 10 each boy get x/(y+10) = (x/y)-1 => x/(y+10) = (x-y)/y .........
(1) now case 2nd if no of boys decrease by 15 each boy get
x/(y-15)= (x/y) +3 => x/(y-15) = (x+3y)/y ...........
(2) solve the equations and get the answer
mahnooriqbal870:
full solution please
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3
But if there were 15 childrn less each would get 3 rupees the sum of money = 5 if there 10 children 10×5 =50 ans
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