Question

A sum two
digit number is 3 more than 4 times the sum of digits if 18 is added to the number the digits are reversed find the number​

Answer 1

Let the number be “ab”

Now ab can be written as “10a+b”

Condition 1 :

10a+b =4(a+b)+3

=>10a+b=4a+4b+3

=> 6a=3b+3

=> 2a=b+1 ————equation (1)

Condition 2 :

Reversed number “ba” =10b+a

10a+b+18= 10b+a

=>9a+18=9b

=>a+2=b ————equation (2)

Compare both the equations

We get a=3,b=5

Therefore the required two digit number is 35