Question

A sweetseller has 420 kaju barfis and 130 badam barfis. She wants to stack them in such a way that each stack has the same number, and they take up the least area of the tray. what is the number of that can be placed in each stack for this pupose.

Answer 1

Total no. of barfis=420+130=550
The total number of barfis in each stack to take up the least space in the tray is 550/2=225 barfis.....

Answer 2

Here ,since it is given that least area, u need to find the HCFof the two,
                so we need to find the HCF of 420 and 130,
                                        so, by euclids division lemma,
                                             420= 130*3+30
                                              130=30*4+10
                                                30=10*3+0
                  Hence, 10 is the HCF and 10 is the required no of sweets
 mplzzzz mark it as the brainliest plz