A tangent PQ at a point P of a circle of radius 5 cm meets a line through the centre O at a point Q so that OQ = 12 cm. Length PQ is : (A) 12 cm. (B) 13 cm (C) 8.5 cm (D) cm
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seems like a mistake in your question the correct question is A tangent PQ at a point P of a circle of radius 5 cm meets a line through the centre O at a point Q so that OQ = 12 cm. Length PQ is : (A) 12 cm. (B) 13 cm (C) 8.5 cm (D) √119cm
According to the question we know that A tangent is PQ at a point of p of the circle at the radius 5cm meets a line through the centre O at point Q and OQ = 12
Need to find length PQ
now,
in ΔPOQ
Here angle P is right angle and we know that right angle is always 90°
so,
Using the Pythagoras theorem
OQ² = PQ² + OP²
now, transfer the PQ² in right side
PQ² = OQ² - OP²
now, putting the above values we get
PQ² = (12)² - (5)²
PQ² = 144 - 25
PQ² = 119
PQ = √119
Hence, the correct answer is √119
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