PQL and PRM are tangents to the circle with centre o at the points Q and R ,respectively and S is a point on the circle such that angle SQL=50 and angle SRM=60. Find angle QSR.
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Answered by
138
SEE THE DIAGRAM ATTACHED
Join Q to R
<QSR = <SQL = 50 degrees
<RQS = <MRS = 60 degrees
Angle between a chord and a tangent equals the angle subtended by the chord at the circumference in the segment opposite the angle
∴ <QSR = 180 - (60+50) = 70 Degrees (Angles of a triangle add up to 180 degrees)
Join Q to R
<QSR = <SQL = 50 degrees
<RQS = <MRS = 60 degrees
Angle between a chord and a tangent equals the angle subtended by the chord at the circumference in the segment opposite the angle
∴ <QSR = 180 - (60+50) = 70 Degrees (Angles of a triangle add up to 180 degrees)
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Answered by
91
Answer:79
Step-by-step explanation:PQO=LQO=90°
SOQ=LQO-LQS
SOQ=40°
SIMILARLY
SRO=30
WE KNOW
OQ,OS,OR are equal radi
There for we have 2 isosceles triangle
So
QSR=40+30=70
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