A taxi charge ₹20 for the first kilometer and ₹12/km for subsequent distance covered, Taking the total distance covered as x km and total fare as y, Write a linear equation depiciting the relation between x and y. also Draw the graph of it. from the graph, find the taxi charges for covering
i) 12 km ii) 20km
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Answer:
Considering
distance = x
fare = Rs.y
taxi charges for 1st km=Rs.20
and for several 1km=20+12Rs
then for next 2km=20+12+12Rs
So we can say that for x km,the fare will be 12x+20 Rs
i.e.,12x+20=y
(i)12km
12(x)+20=y
12(12)+20=y
44=y
so for 12km the charges will be 44Rs
(ii)20km
12(20)+20=y
260=y
So, for 20km the charges will be Rs.260
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