Question

a taxi charges rs 20 for the first km and @ rs 12 per km for subsequent distance covered. taking the ditance covered as x km and total fare rs y,write a linear equation depicting the relation in x and y.

Answer 1

Answer:

y = 12x + 8

Step-by-step explanation:

Given that it costs Rs. 20 for the first km and Rs. 12 per km for every subsequent km.

So It is also given that, Distance covered is x and Total Fare is Rs. y

Linear Equation according to the question would be:

Total Distance = x

Rate for first km is 12. So Rate for remaining distance is ?

⇒ Remaining Distance = ( x - 1 )

⇒ Rate = 12 ( x - 1) = 12x - 12

Total Fare for the whole distance is Rs. y

⇒ y = 12x -12 + 20

⇒ y = 12x + 8

This is the required equation.

Hope it helped !!

Answer 2

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Step by Step Explanation ;-
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Given ;

• Cost for the First km = ₹ 20
• Cost for every subsequent km = ₹ 12 per km.

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As Given Too ;

• Distance covered = X
• Total Fare = Y

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• Now , the linear equation for representing the quation will be ;

-> Total Distance = X

Then , Rate of Remaining Distance ;-

=> Remaining Distance = ( X - 1 )

=> Rate = 12 x ( X - 1 ) = 12X - 12

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• Now , as given "Y" to be the total distance of the fare ; So :-

=> Y = 12X - 12 + 20

=> Y = 12X + 8

Now , the resultant is the Required Equation.

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- Regards
@dmohit432