a taxi charges rupees 20 for the first kilometre and rupees 12 per kilometre for the subsequent distance covered taking the distance cover as x km and total fare as rupees y write a linear equation depicting the relation in X and Y.draw the graph between x and y and from the graph find the taxi charges for covering 16 kilometre.
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y=20+12(x-1)
y=20+12x-12
y=8+12x. (equation)
if x=16 then y=8+12×16
y=8+192
y=200 ans.
y=20+12x-12
y=8+12x. (equation)
if x=16 then y=8+12×16
y=8+192
y=200 ans.
amishi123a:
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