Question

A teacher divided her class of 40 students into 8 equal groups. She asked 2 of the groups to go to the computer lab and the rest to go to the activity room. How many students went to the computer lab?

Answer 1

Answer:

➪Let the first group students be x

➪Then second group is x-5

➪now fifth group is x-5

➪then forth group is (X-5)+3

➪now third group is [(x-5)+3]+2

➪now

➪the total sum is 48

➪thus

➪x+x-5+x-5+(x-5)+3+[(x-5)+3]+2 = 48

↬now solve and get the answer

$❀✿THA᭄NKS★$

Answer 2

Answer:

hey mate

hope it helps you