A tent is in the form of a cylinder of radius 2.10 m and height 4 m , surmounted by a cone of equal base and height 2.8 m. Find the capacity of the tent.
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Answer:
Given:
Height (h) of the cylindrical part = 2.1 m
Diameter of the cylindrical part = 4 m
Radius of the cylindrical part = 2 m
Slant height (l) of conical part = 2.8 m
Area of canvas used = CSA of conical part + CSA of cylindrical part
=πrl+2πrh
=π×2×2.8+2π×2×2.1
=2π[2.8+4.2]
=2×
7
22
×7
=44m
2
Cost of 1 m
2
canvas =500 rupees
Cost of 44 m
2
canvas =44×500=22000 rupees.
Therefore, it will cost 22000 rupees for making such a tent.
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