Question

A tent is in the form of a right circular cylinder 24m.The height of cylinder portion is 11m while the vertex of cone is 16m above the ground find the area of canvas required for the tent.

Answer 1

Answer:

Step-by-step explanation:

CSA of cylinder=2*pi*r*h

=2×22/7×24/2×11

=829.71 m^2

Then,

slant height=root r^2+h^2

=root 12^2+(16-11)^2

=root 144 + 25

Hence, slant height=13 m

Now,

CSA of cone=pi*r*l

=22/7×12×13

=490.28 m^2

Then,

Total area of canvas required for tent

=829.71+490.28

=1319.99 m^2

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