Question

A thin copper wire of length l increases in length by 1% when heated through 30degrees if a thin

Answer 1

as ∆l=1%=1/100=0.01

so l=1cm

T=30°c

as, ∆l=l×alpha×t

0.01=1×a×30


a=0.01/30

=3.33×10^-4 °c^-1
hope it helped