Question

A thin strip of iron with a mass of 15.5g is placed into a solution containing 21.0g
of copper (II) sulfate and copper begins to form. After some times, the reactions
stops because all the copper (II) sulfate has reacted. The iron strip is found to
have a mass of 8.5g. The mass of copper formed is found to be 8.60g. What
mass of iron (II) sulfate has been formed in the reaction?

Answer 1

Explanation:

Mass of iron = Initial mass – Final mass

= 15.5 – 8.5 = 7.0g

Mass of copper (II) sulfate = 21.0g

Mass of copper = 8.60g

According to law of conservation of mass,

Mass of iron + Mass of copper (II) sulfate = Mass of copper + Mass of iron (II) sulfate

7.0g + 21.0g = 8.60g + Mass of iron (II) sulfate

So, Mass of iron (II) sulfate = 19.40g

Answer 2

Answer:

16.04 is the correct answer