Question

a tiger is moving on a circular path of radius 21 it starts from p and reaches Q the distance covered by the toy car is 33 calculate the displacement of the Tiger ​

Answer 1

Answer:

29.7 units

Step-by-step explanation:

Circumference of circular path = 2$\pi$r = 2* 22/7 * 21 = 132 units

Distance covered by the tiger is 33 units, which is a quarter of the circumference, Therefore, triangle formed by joining the points of center of the circle, starting point and final point, is a right triangle

∴ $Displacement^{2} = 21^{2} + 21^{2}$

$Displacement = \sqrt{441 + 441}$

$Displacement = 29.7$

Answer 2

Answer:

29.7 units (approx.)

Step-by-step explanation:

r = 21 units

circumference = 2πr = 2*22/7*21 = 132 units

distance covered = 33 units = 1/4 * circumference

so it is a quadrant, so angle is 90

hence, right angled triangle...

displacement is the hypotenuse of the triangle

by Pythagoras Theorem,

displacement = $\sqrt{21^{2}+21^{2} }$ = $\sqrt{441+441}$ = $\sqrt{882}$ = 29.7 units (approx.)

mark brainliest