Math, asked by Shubham8148, 1 year ago

a took 45 minute to walk 15km. if B is 50% faster than A how much time he will take to cover the same distance

Answers

Answered by shivamdalmia
0
Time taken by A is 45 min or 3/4 hr

Speed of A will be = 15 ÷ (3/4)

15 X 4/3 = 20 km/hr

B is 50% faster than A means B has speed of A + 1/2 speed of A

So we get,

20 + (1/2)20 = 20 + 10 = 30 km/hr

Speed of B = 30 km/hr

So to cover 15 km it will take B half hr or 30 mins

Similar questions