a torch bulb is rated 2.5 volt and 750 milliampere calculate its power and resistance and energy consumed by the Parliament 4 hour
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Answered by
9
Given :
V=2.5 V
I=750mA= 750x10⁻³A
power =p=?
Power =V*I
=2.5x750x10⁻³
=1.875W
reistance :
V=IR
R=V/I=2.5/750x10⁻³=3.3 ohms
Energy consumed if bulb is lighted for 4 hours :
E=p*t=1.875x4=7.500Wh=27x 10³ joules
V=2.5 V
I=750mA= 750x10⁻³A
power =p=?
Power =V*I
=2.5x750x10⁻³
=1.875W
reistance :
V=IR
R=V/I=2.5/750x10⁻³=3.3 ohms
Energy consumed if bulb is lighted for 4 hours :
E=p*t=1.875x4=7.500Wh=27x 10³ joules
Answered by
5
Hii mates answer is there
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