Physics, asked by ankur114, 1 year ago

a torch bulb rated 2.5 volt 750 milliampere calculate first it's worth second its resistance and energy consumed by the bulb in 4 hour

Answers

Answered by ADAMSHARIEFF
1
Given :
V=2.5 V
I=750mA= 750x10⁻³A
power =p=?
Power =V*I
=2.5x750x10⁻³
=1.875W
reistance :
V=IR
R=V/I=2.5/750x10⁻³=3.3 ohms
Energy consumed if bulb is lighted for 4 hours :
E=p*t=1.875x4=7.500Wh=27x 10³ joules
Answered by TheKingOfRandom
2
Given

V = 2.5
I = 0.75

Power = V × I
Power = 2.5 × 0.75
Power = 1.875 W

Resistance = V ÷ I
Resistance = 2.5 ÷ 0.75
Resistance = 3.33 ohm

Energy consumed in 4 hours,

Energy consumed = Watt × hours
Energy consumed = 1.875 × 4
Energy consumed = 7.5 Wh
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