Question

A tower casts a shadow that is 60 feet long when the angle of elevation of the sun is 65 ̊ How tall is the tower?

Answer 1

Answer:

Height of the tower is 128.67 ft.

Step-by-step explanation:

In the attachment I have answered this problem.

See the attachment for detailed solution.

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Answer 2

Answer:

128.67 feet.

Step-by-step explanation:

Refer the attached figure

Length of Shadow i.e. BC = 60 ft.

The angle of elevation of the sun i.e. ∠ACB =  65 ̊

Height of tower = AB

Use trigonometric ratio

$tan\theta = \frac{Perpendicular}{Base}$  

$2.1445 = \frac{AB}{60}$  

$2.1445  \times 60 = AB$  

$128.67 = AB$  

Hence the height of the tower is 128.67 feet.