A tower is 100 root 3 m high find the angle of elevation of it's top when observerd from a point 100m away from the foot of the tower?
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Answer:
Θ=60°
Step-by-step explanation:
Height= 100√3 m
Distance from the tower and the observer= 100 m
tanΘ= opposite/adjacent
tanΘ=100√3/100
tanΘ=√3
Θ=60° [since, tan60°=√3]
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