Question

Calculate the oxidation number of mn in kmno4 , mno4 -2

Answer 1

Explanation:

1)Let the Ox.no. of Mn in KMnO4

be x.

We know that, OX.no. of K=+1

Ox.no. of O2=-2

+1+x+(-2)*4

+1+x-8=0

x=+7

2)let the ox.no.of mn in mno4-2

be x

x+(-2)*4=-2

x-8=-2

x=+6

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