Math, asked by tanisha1697, 3 months ago

A town had 10,000 residents in 2000. Its population declines at a rate of 10% per annum. What
will be its total population in 2005?

Answers

Answered by shankarkuchibhotla
3

Step-by-step explanation:

at 2001

10000- 10% of 10000

10000-1000 =9000

at 2002

9000-10%of 9000

9000-900

8900

at 2003

8900-10% of 8900

8900-890

8010

at 2004

8010-10% of 8010

8010-801

7209

7209- 10% of 7209

7209-720.9

6488.1

round figure 6488

HOPE THIS HELPS.

Answered by beenamanu
11

Answer:

Decline rate = 10 %

Population decrease in 2001 = 10,000 x 10/100 = 1,000

Population decrease in 2002 = 9,000 x 10/100 = 900

Population decrease in 2003= 8100 x 10/100 = 810

Population decrease in 2004 = 7290 x 10/100 = 729

Population in 2005 = 7290 - 729 = 6561

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