Question

prove that (1+tanA - secA) × (1+tanA+ secA) = 2tanA​

Answer 1

Step-by-step explanation:

=> let multiply

1 + tanA + secA + tanA + tan² + tanAsecA - secA - secAtanA - secA²

=> let cancel same terms

1 + 2tanA + tan²A - sec²A

( :- we know that sec²A - tan²A = 1 then

multiply with -1 => tan²A - sec²A = -1 )

1 + 2tanA - 1 = 2tanA

( :- hence proved)

I hope this will help you dear..

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Answer 2

Answer:

Let's multiply

1+tanA+secA+tanA+tan²+tanAsecA-secA-secAtanA-secA²

now cancel same terms

1+2tanA+tan²A-sec²A

since, we know that sec²A-tan²A= 1 then multiple with -1 => tan²A-sec²A = -1

1+2tanA-1 = 2tanA

hence proved