A toy is in the form of a right circular cylinder with a right circular cone fixed above it.The diameter and the height of cylindrical part of the toy are126 cm and 5 cm respectively. The total height of the toy is 21 cm. Find the total surface area of the toy.
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Hi ,
i ) dimensions of the cylinder:
Diameter of the base = d = 126cm
Radius = d/2
r = 126/2 = 63cm
Height = h = 5cm
ii) Dimensions of the cone:
radius = r = 63 cm
Height of the cone
= total height of the toy - h
= 21 - 5
H = 16 cm
Slant height = l
l^2 = r^2 + h^2
= 16^2 + 63^2
= 3969 + 256
= 4225
l = sqrt(4225)
l = 65 cm
iii ) Total surface area of the toy
= lateral surface area of the cylinder
+ base area of the cylinder +
curved surface area of the cone
= 2× pi×rh + pi × r^2 + pi × r l
= pi × r [ 2h + r + l ]
= 22/7 × 63 [ 2× 5 + 63 + 65 ]
= 22 × 9 ( 10 + 63 + 65 )
= 198 × 138
= 27324 Square cm
Therefore ,
Total surface area of the toy = 27324
Square cm
I hope this helps you.
***
i ) dimensions of the cylinder:
Diameter of the base = d = 126cm
Radius = d/2
r = 126/2 = 63cm
Height = h = 5cm
ii) Dimensions of the cone:
radius = r = 63 cm
Height of the cone
= total height of the toy - h
= 21 - 5
H = 16 cm
Slant height = l
l^2 = r^2 + h^2
= 16^2 + 63^2
= 3969 + 256
= 4225
l = sqrt(4225)
l = 65 cm
iii ) Total surface area of the toy
= lateral surface area of the cylinder
+ base area of the cylinder +
curved surface area of the cone
= 2× pi×rh + pi × r^2 + pi × r l
= pi × r [ 2h + r + l ]
= 22/7 × 63 [ 2× 5 + 63 + 65 ]
= 22 × 9 ( 10 + 63 + 65 )
= 198 × 138
= 27324 Square cm
Therefore ,
Total surface area of the toy = 27324
Square cm
I hope this helps you.
***
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hope I will help you
OM NAMAH SHIVAAY
OM NAMAH SHIVAAY
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