Question

A toy is in the shape of a right circular cylinder with a hemisphere on one end and cone on the other the radius and height of the cylinder girl part are 5 cm and 13 cm respectively the lady of Anas hemispherical and parts are the same as that of the cylindrical part find the surface area of the toy if the total height of the cone is 30cm

Answer 1

radius of cylinder=r=5cm
height of the cylinder= h=13cm
height of cone=H= 30cm
we need slant height or 'l' to find CSA OF CONE
l=√h^2+r^2
=√900+25
=30.4cm

surface area of toy= (CSA of hemisphere)+(CSA of cylinder)+(CSA of cone)
=(2πr^2)+(2πrh)+(πrl)
=(2×22/7×25)+(22/7×5×13)+(22/7×5×30.4)
=(157.1)+(204.2)+(477.7)
=839cm^2

there fore,
surface area of toy is 839cm^2

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