Question

A toy of rocket of mass 1 kg, is modelled as a particle. It is launched from rest using its engines which produce a force of size (20-t)N and have enough fuel for five seconds. After five second the rocket will be subject to one force only; its weight , a. Show that, for 0

Answer 1

Explanation:

Using the velocity v=u−gt+v,ln(

m

m

0

)

Here u=0,t=60s,g=10m/s

2

,v=2000m/s,m

0

=1000kg

and m=1000−10×60=400kg

We get v=0−600+2000ln(1000/400)

orv=2000ln2.5−600

= 200{10 In 2.5 - 3) = 1232.6 m/s

Hence, maximum velocity of the rocket is 1232.6 m/s.

Answer 2

Answer:

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