A traider baught a number of articles for 900 Five articles were found damaged.he sold remaining of each articles at 2 more than what he paid for it.he got a profit of 80 on a whole transaction. Find the no. Of articles he bought
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Hlw mate
Number of articles=x( say)
therefore c.pof per article= 900/x
profit on s.p= (x-5)2
real profit=( x-5)2- 5(900/x)
given profit = 80
therefore(x-5)2-5(900/x)= 80
2x- 10-4500/x= 80
2x^2 -10x- 4500= 80x
x^2 -5x-2250=40x
x^2-45x- 2250=0
x^2-75x+30x-2250=0
(x-75)(x+30)=0
therefore,
number of articles=75
Hope it helpful
Number of articles=x( say)
therefore c.pof per article= 900/x
profit on s.p= (x-5)2
real profit=( x-5)2- 5(900/x)
given profit = 80
therefore(x-5)2-5(900/x)= 80
2x- 10-4500/x= 80
2x^2 -10x- 4500= 80x
x^2 -5x-2250=40x
x^2-45x- 2250=0
x^2-75x+30x-2250=0
(x-75)(x+30)=0
therefore,
number of articles=75
Hope it helpful
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