Question

if an object starts with speed 10 metre per second and with an acceleration 2 metre per second square what will be its distance in 10 seconds

Answer 1

thanks for your question it is your answer

Answer 2

m
$s = ut + ( \frac{1}{2} ) \times a \times {t}^{2}$
s = distance in t second
u= initial velocity
a=acceleration
t = time
suppose initial velocity is 0
$acceleration to be \: \frac{10m}{ {s}^{2} }$
s(2)=
$s(2) = ( \frac{1}{2}) \ \times 10 \times {3}^{2}$
$s(2) = 45 meters$
$s(3) = ( \frac{1}{2} ) \times 10 \times {2}^{2}$
$s(3) = 20 \: meters$

now distance traveled in 3rd sec = 45 meters-20 meters-20= 25 meters.