Question

A train 200 m long crosses a bridge 600 m long. It enters the bridge with speed of 30 m/s and leaves it with a speed of 50 m/s. If acceleration of train is constant throughout the motion then acceleration (in m/s2) of train is​

Answer 1

Answer:

800m per hour.

Explanation:

And it took 2hrs.

Hope you understand this

Answer 2

Answer:

The acceleration of the train is 1m/s².

Explanation:

The acceleration of the train is calculated as,

$a=\frac{v^2-u^2}{2s}$    (1)

Where,

a=acceleration of the object

v=final velocity with which the object is moving

u=initial velocity with which the object is moving

s=total distance traveled by the object

From the question we have,

The initial velocity(u)=30m/s

The final velocity(v)=50m/s

The total length traveled(s)=200m+600m=800m

By inserting the values in equation (1) we get;

$a=\frac{50^2-30^2}{2\times 800}$

$a=\frac{2500-900}{2\times 800}$

$a=\frac{1600}{1600}$

$a=1m/s^2$

Hence, the acceleration of the train is 1m/s².

#SPJ3