Question

a train acceleration uniformly from 36km/h to 72km/h in 20 second find the distance travell

Answer 1

U=36km/h=10m/s
V=72km/h=20m/s
V=u+at
a=v-u/t
a=20-10/20
=1/2
V^2-u^2=2as
S=20×20-10×10/0.5×2
S=400-100
=300m