A train covers half of its journey with a speed of 30 m/s and other half with speed of 40 m/s. Calculate it's average speed for the entire journey?
Answers
Answered by
438
s = total distance. t1 and t2 are durations for covering half total distance.
s/2 = 30 * t1
s/2 = 40 * t2
So total time duration = t1+t2 = s*[1/60 + 1/80]
Avg velocity = s/(t1+t2)=
240/7 m/s= 34.28 m/s
s/2 = 30 * t1
s/2 = 40 * t2
So total time duration = t1+t2 = s*[1/60 + 1/80]
Avg velocity = s/(t1+t2)=
240/7 m/s= 34.28 m/s
Answered by
146
speed = distance/time
Take time for speed 1 as t1 and speed 2 as t2
So, average speed = d/(t1+t2)
speed 1,
30 = d/2t1
t1 = d/2*30 ---------------1
speed 2,
40 = d/2t2
t2 = d/2*40 --------------2
Add 1 and 2 to find average speed,
t1+t2 = d/60 +d/80
t1+t2 = d[1/60 +1/80]
t1+t2 = d *[7/240]
average speed, d/(t1+t2) =240/7 = 34.28 m/s
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