Question

A train crosses a man travelling in another train in
the opposite direction in 8 seconds. However, the train
requires 25 seconds to cross the same man if the trains
are travelling in the same direction. If the length of the
first train is 200 metres and that of the train in which
the man is sitting is 160 metres, find the speed of the
first train.​

Answer 1

A train crosses a man travelling in another train in  the opposite direction in 8 seconds. However, the train  requires 25 seconds to cross the same man if the trains  are travelling in the same direction. If the length of the  first train is 200 metres and that of the train in which  the man is sitting is 160 metres, find the speed of the  first train.​

Step-by-step explanation:

A Train crosses a man travelling in another train in the opposite direction in 8 seconds.

(St + Sm) X t = Lt

(St + Sm) X 8 = 200

St + Sm = 200/8 = 25

Let Sm be speed of a man’s train.

the train needs 25 seconds to cross the same man if the trains are travelling in the same direction

(St - Sm) X t = Lt

(St - Sm) X 25 = 200

St - Sm = 200/25 = 8

We have two unknowns and two equations. When we solve them we get St = 16.5 m/s or 59.4kmph