a train is moving with a velocity of 36 km per hour to 54 km per hour in 10 seconds acceleration and
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Answered by
0
convert km/hr to m/s
multiply km/hr by 5/18
so
U - initial velocity = 10m/s
V - Final velocity = 15m/s
accln = (V-U)/t
= 5/10
=0.5m/s^2
Answer is 0.5m/s^2
multiply km/hr by 5/18
so
U - initial velocity = 10m/s
V - Final velocity = 15m/s
accln = (V-U)/t
= 5/10
=0.5m/s^2
Answer is 0.5m/s^2
Answered by
1
Initial speed u = 36 km/h = 36 x 1000/3600 m/s = 10 m/s
Final speed v = 54 km/h = 54 x 1000/3600 m/s = 15 m/s
Time t = 10 s
Acceleration a = (v - u)/t = (15 - 10)/10 = 5/10 = 0.5 m/s2.
Distance travelled S = ut + ½ at2
= 10 x 10 + ½ x 0.5 x 10 x 10 m
= 100 + 25 = 125 m
Final speed v = 54 km/h = 54 x 1000/3600 m/s = 15 m/s
Time t = 10 s
Acceleration a = (v - u)/t = (15 - 10)/10 = 5/10 = 0.5 m/s2.
Distance travelled S = ut + ½ at2
= 10 x 10 + ½ x 0.5 x 10 x 10 m
= 100 + 25 = 125 m
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