Question

A train is running at 7/11 of its own speed reached a place in 22 hours. How much time could be saved if it would run at its own speed?

Answer 1

Let original speed be V m/s. let distance be S m. using distance formula S = 7V/11 * 22hr =14V When train running at original speed S(Distance)=V(Original speed)*time =>time=14V/V =14 hr 
So it'll save (22-14)=8 hrs.