A train is targeted from Delhi to Mumbai at an average speed of 80 km/h but due to repairs of track loses 2 hrs in the first part of the journey. If then accelerates at a rate of 20 km/h2 till the speed reaches 100 km/h. Its speed now maintained till the end of the journey. If the train now reaches station in time. Find the distance from when it started accelerating.
Answers
Answer:
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Explanation:
If then accelerates at a rate of 20 kph^(2) till the speed reaches 100 kph. Its speed is now maintained till the end ofthe journey. ... to Pune at an average speed of 80 kph but due to repairs of track looses 2hr sin the first part of the journey. If ... A carrier train, when it is 100 km away from the station, going at.
Answer:
Let the total distance travelled be L km and total time taken be t hrs. Let for x1 distance it travels with speed 80kmph for time t1. And after that let it started accelerating, let the time taken to attain speed 100kmph be t2 hrs and distance travelled during this be x2 km. Let x3 be the distance travelled in time t3 after attaning speed 100 kmph . Thus ,the required length of path we need to calculate is L-x1.
