a train is traveling at the speed of 90kmh-1 brakes are applied so as to produce a uniform acceleration o.5ms-2 . find how far the train will gobefre it is brought to rest.
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here we go with your question,
u (initial velocity) = 90 km/h
v (final velocity) = 0 km/h {because brakes are applied}
a (acceleration) = 0.5 m/s
we have to find t (time)
we know that,
a = (v-u)/t
0.5 = (0-90)/t
0.5 = -90/t
NOW CROSS MULTIPLY,
so, t = -90/0.5
t = -180 seconds
t = 3 minutes
u (initial velocity) = 90 km/h
v (final velocity) = 0 km/h {because brakes are applied}
a (acceleration) = 0.5 m/s
we have to find t (time)
we know that,
a = (v-u)/t
0.5 = (0-90)/t
0.5 = -90/t
NOW CROSS MULTIPLY,
so, t = -90/0.5
t = -180 seconds
t = 3 minutes
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