A train is travelling at a speed of 90 km h–1. Brakes are applied so as to produce a uniform acceleration of – 0.5 m s-2. Find how far the train will go before it is brought to rest.
NCERT Class IX
Sciences - Main Course Book
Chapter 8. Motion
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u = 90 km/hr = 90 * 5/ 18 = 25 m/sec
a = - 0.5 m/sec/sec
v = 0
s = (v^2 - u^2) / 2 a
= (0 - 25^2) / (2 * -0.5)
=> s = 625 meters
a = - 0.5 m/sec/sec
v = 0
s = (v^2 - u^2) / 2 a
= (0 - 25^2) / (2 * -0.5)
=> s = 625 meters
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