A train is travelling at a speed of 90 km/h . Brakes are applied so as to produce a uniform acceleration of -0.5m/s^2. Find how far the train will go before it is brought to rest.
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Initial velocity=90 km/h=25m/s
Final velocity=0
acceleration= -0.5 m/s^2
v^2=u^2+2aS
0^2=25^2+ 2× -0.5× S
0=625-S
S=625
Therefore distance traveled is 625 m before it will come to rest.
Final velocity=0
acceleration= -0.5 m/s^2
v^2=u^2+2aS
0^2=25^2+ 2× -0.5× S
0=625-S
S=625
Therefore distance traveled is 625 m before it will come to rest.
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