A train is travelling at s speed of 90km/hr.brakers are applied so as to produce a unifrom acceleration of 0.5m/s2 .find how far the train will go before it is brought to rest
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Starting Velocity (u) = 90km/h = 25m/s
Last Velocity (v) = 0
Acceleration(a) = - 0.5 m/s^2 = -1/2 m/s^2
Suppose the distance covered = (s) metres.
So, By Newton's Third Equation =>
v^2 = u^2 + 2as
0 = (25)^2 + 2×(-1/2)×s
0 = 625 - s
Distance (s) = 625 metres.......●
Hope it was helpful. Please mark as brainliest.
Last Velocity (v) = 0
Acceleration(a) = - 0.5 m/s^2 = -1/2 m/s^2
Suppose the distance covered = (s) metres.
So, By Newton's Third Equation =>
v^2 = u^2 + 2as
0 = (25)^2 + 2×(-1/2)×s
0 = 625 - s
Distance (s) = 625 metres.......●
Hope it was helpful. Please mark as brainliest.
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