Question

A train leaves delhi at 6.00
a.m. and reaches agra at 10.00
a.m. another train leaves agra at 8.00
a.m. and reaches delhi at 11.30
a.m. at what time do the two trains cross each other if the distance between delhi and agra is 200 km?

Answer 1

Solution :-

given that,

• Time taken by train A from delhi to agra = 10 - 6 = 4 hours .
• Time taken by train B from agra to delhi = 11:30 - 8 = 3 : 30 = 3(1/2) = (7/2) hours .
• Distance between Delhi to agra = 200 km .

so,

→ Speed of Train A = D / S = 200 / 4 = 50 km/h .

→ Speed of Train B = D/S = 200 (7/2) = (400/7) km/h .

now,

→ from 6AM to 8AM distance covered by Train A = 50 * 2 = 100 km .

then,

→ Distance left = 200 - 100 = 100 km/h .

and,

→ usual speed of both trains = 50 + (400/7) = (350 + 400)/7 = (750/7) km .

therefore,

→ Time taken by them to cover 100 km = D/S = 100/(750/7) (700/750) hours = (14/15) * 60 = 56 minutes.

Hence, Both trains cross each other at 8 : 56 AM .

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