a train moves with constant speed 36 kmh in 10minutes with another constant speedcof 45kmh in mext 10 minutes and then with an acceleration of 5ms in the last 10minutes calculate the average speed of train for journey and the total distance travelled
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velocity1=36kmph=10mps
distance1=10×10×60=6000m
velocity2=45kmph=12.5mps
distance2=12.5×10×60=7500m
distance3=12.5×10×60+5×600×600/2= 907500m
net distance=6000+7500+907500= 921000m
average speed=921000/(30×60)= 3070/6 mps
=511.66mps
distance1=10×10×60=6000m
velocity2=45kmph=12.5mps
distance2=12.5×10×60=7500m
distance3=12.5×10×60+5×600×600/2= 907500m
net distance=6000+7500+907500= 921000m
average speed=921000/(30×60)= 3070/6 mps
=511.66mps
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